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Samus Aran [Discussion]

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Re: Samus Aran [Discussion]

Postby Alpha or Omega » Thu Oct 02, 2014 12:36 am

I'm pretty sure geemers in Metroid Prime are different from the ones in the 2-D Metroid games.
They may be in the same species and from the same planet, but that's where it ends.
We see that the spikes that geemers have in Metroid Prime are longer and they shrug off power beam attacks along with ice beam and the wave beam, while the ones on Zebes and the bottle ship are not quite the same.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Thu Oct 02, 2014 9:33 am

Alpha or Omega wrote:I'm pretty sure geemers in Metroid Prime are different from the ones in the 2-D Metroid games.
They may be in the same species and from the same planet, but that's where it ends.
We see that the spikes that geemers have in Metroid Prime are longer and they shrug off power beam attacks along with ice beam and the wave beam, while the ones on Zebes and the bottle ship are not quite the same.


They are, but the problem is that Samus takes damage from a Geemer on Tallon IV, whereas she's unharmed by certain spikes on Zebes. The latter produces greater pressure than the former. If it was the Geemer that was producing higher pressure than the spike, then we could say, "This is the amount of pressure Samus is unharmed by." I figure there's going to be inconsistencies anyway, so it's not going to be so simple when we see contradictions.

Edit: I'm using this image now. Samus is 43 px. The thickness of the spike pointing down (since that's the simplest to calculate) is only 2 px.

2 px. / 43 px. = 0.0465116279069767

190 cm. * 0.0465116279069767 = 8.837209302325573 cm., or 88.37209302325573 mm.

The tip is 1 px.

1 px. / 43 px. = 0.0232558139534884

190 cm. * 0.0232558139534884 = 4.418604651162796 cm. or 44.18604651162796 mm.

This is equal to 3,223,467.4352114 N. This force over an area of 44.18604651162796 mm^2 is 72.95215774426 gigapascals, which is higher than the spike Samus stood on. So that's consistent, at least. In-game, Geemers are difficult to determine because of how their spikes are designed. In the Metroid Prime series, their spikes are detailed better, so show a much better appearance of sharpness.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Sat Oct 04, 2014 1:45 am

Mohs scale and Samus' energy shield
Lately I've been testing Samus' armor in terms of indentation hardness. This is with the basis of steel in mind, since Samus' armor is metallic, according to Metroid Prime in Frigate Orpheon where the scan says for Samus to place a metallic sphere in the slot. (This is where Samus must use her Morph Ball mode.) Of course, as I said before, chances are Samus' armor is harder than steel under the notion that the armor is of alien origin. This is with respect to Samus' energy shield, however. If we accept the calculation of the spikes Samus can stand on without any damage, then we have an idea of what Samus can withstand without any harm.

Now I want to refer to scratch hardness. The idea of Mohs hardness scale is that if object A scratches object B, then A is harder than B. If A cannot scratch B, then even if there isn't a noticeable scratch, A and B can be said to have similar or the same hardness. According to official Metroid data, Kraid's claws can shred iron. Warp Wasps have stingers that can shear steel. This means Kraid's claws are harder than iron and War Wasps have stingers harder than steel. (War Wasps have extremely thin stingers, which can add to the high pressure.)

Does this mean that Samus' armor is made of iron or steel? Not quite. We know that these two creatures have natural abilities that are harder than iron and/or steel. (Let's face it, there are creatures in Metroid that can survive magma, so it's not out of the realm of possibilities.) I'm not going to find out the hardness from these, but I suppose I could go a bit higher for Samus' armor being steel.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Fri Oct 10, 2014 11:39 am

Samus' plasma beam and Ridley's heat resistance
We know Ridley travels through space and we have observed him passing through atmospheric temperatures that would be 3,000 degrees Fahrenheit. This would mean Ridley can withstand that type of heat without any problems. However, Ridley must be capable of exceeding this temperature.

Samus' plasma beam produces an unknown temperature, but it must also be higher than 3,000 degrees Fahrenheit as well because at this temperature, humans take a few hours to be cremated. And of course, Samus is dealing with space pirates, not humans. So I'd imagine Samus's plasma beam exceeds 3,000 degrees Fahrenheit.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Sat Oct 11, 2014 10:42 am

What material is Samus' armor made of?
If you hoped I knew the answer, I apologize for disappointing you. Yesterday, I thought about magnetic rails and how Samus needs the Spider Ball to traverse these. This had me thinking that Samus' armor is non-ferrous. All right, so there are ferro-magnetic, non-ferrous metals, but Samus' isn't magnetic.

Titanium comes to mind. It is non-magnetic. I can't say this is what the armor is made of, or that it is the only metal, since other materials are combined with titanium. The Power Suit is of alien origin and we know other metals and non-metals exist in the Metroidverse. Still, I thought this was worth noting.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Thu Oct 16, 2014 2:22 pm

The black hole created by the Nightmare and its gravity
I'm probably approaching this the wrong way, but I'm going to be using the Schwarzschild radius, which is R = Gm/c^2, where R is the radius, G is the gravitational constant, m is the mass of the object, and c^2 is the speed of light squared. Well, if I took the mass of a planet like Jupiter, this would give me 1.898 * 10^27 kg., but the size of the black hole created by the Nightmare is somewhat smaller, at least 97% of Jupiter's mass. So if we with with the gravitational acceleration of Jupiter (24.79 m/s^2), we'd end up with 24.05 m/s^2, or 2.45 g.

I know there are other methods for finding the gravity and mass of a black hole, so this is likely an incorrect method, as this is only supposed to find the Schwarzschild radius.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Thu Oct 16, 2014 7:39 pm

Finding the gravity produced by the Nightmare
I'm still trying to figure out how much gravity was produced by the Nightmare. Since both games require different ways of calculation, I'm going to attempt calculating the gravity in Metroid Fusion using Samus from that game. I will understand Samus' height as being 1.98 m. Based on this image, I managed to get Samus' height in pixels, which is 109 px. This is from her feet to her head. However, I need to also find out the distance between the bottom of the missile and the ground, as seen here.

There are 46 px. from the bottom of the missile to the top of Samus' head. 46 px. / 109 px. is 0.4220183486238532, which when we multiply this by 1.98 m., we end up with 0.835596330275229336 m. Adding this to 1.98 m. gives us a distance of 2.815596330275229336 m. This is how far the missile is from the ground. Using the equation to find the gravity, we can learn how much the gravity was increased. The time the missile takes to fall to the ground once it is at its peak is 27 milliseconds.

g = 2(h) / t^2
g = 2(2.815596330275229336 m.) / (0.270 s)^2
g = 5.631192660550458672 m. / 0.0729 s
g = 77.245441159814247901235 m/s, or 7.88 g

Well, I think this is one of the best calculations I've done for determining the gravity produced by the Nightmare. This, of course, is contrary to the previous calculations of the gravity produced by the Nightmare. The flaws from the previous calculations would be from the fact that I used Samus' pixels from Metroid: Zero Mission and applied this to Metroid: Other M and Metroid Fusion. I also assumed the missiles traveling 100 m. (which is fine) and the distance the speed of the missiles. I didn't do this here. I know the errors that can be caused by using pixels to determine feats, but with respect to the increase of gravity by the Nightmare, I think because we're dealing with a character who can alter gravity, the error is non-applicable.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Sat Oct 25, 2014 9:56 am

Samus, pressure, and force
Pressure is different from force, since pressure is force over the surface area. Taking this image again, I will simply address pressure because I was using Brinell's hardness test, which I know was incorrect, since this is not the way to determine pressure. Taking normal force, which is mass times gravity, I will then be able to find the pressure. Gravity is usually 9.81 m/s^2, but this is equal to 9.81 N/kg. We know Samus is 90 kg., so 9.81 N/kg times 90 kg. is 882.9 N. The surface area of the spike that I calculated was 2.753623188405796 cm. 882.9 N / 2.753623188405796 cm^2 is 3.2063 MPa.

I know walking on a bed of nails won't cause any physical damage, since the pressure is evenly distributed over the surface area, this might explain why the nails that are in motion harm Samus, since the nails are no longer even, as the image in the link demonstrates. The image also shows more spikes in a different form that drop down on Samus and slowly rise up. These spikes also have the same surface area. Samus won't take damage from these unless they come down on her. So we could say a pressure of 3.2063 MPa won't harm Samus, especially since 882.9 N doesn't harm Samus, as dashing at Mach 2 would produce 61,740 N.

Edit: So, it turns out Samus' height in pixels in this image is actually 86 px., not 69 px. I don't know how I miscounted. 1 px. / 86 px. is 0.0116279069767442. 198 cm. * 0.0116279069767442 is 2.3023255813953516 cm. Samus' normal force is 882.9 N and 882.9 N / 2.3023255813953516 cm^2 is 3.8348 MPa.

Edit 2: I learned that the spikes are 2 px., not 1 px. like the other calculation. 2 px. / 86 px. is 0.0232558139534884. 198 cm. * 0.0232558139534884 is 4.6046511627907032 cm. 882.9 N / 4.6046511627907032 cm^2 is 1.9174 MPa. Well, now I want to take the gravitational potential energy, but only find the newtons, not joules, and see how many pascals Samus can withstand. Though the distance between the ceiling and Samus is about 3 Samus' high, I'll ignore the third Samus because if her head is coming in contact with the ceiling, then I'm only going to be concerned with the distance from her feet down.

This means the distance is 2 Samus' high with an additional pixels, or 396 cm. The rest of the pixels add up only to 3 px., so 3 px. / 86 px. is 0.0348837209302326 * 198 cm. is 6.9069767441860548 cm. So the distance is 402.9069767441860548 cm. Using gravitational potential energy, which is U = mgh, where m is mass, g is gravity, and h is height, we end up with U = (90 kg.)(9.81 N/kg.)(402.9069767441860548 cm.). This is equal to 355,726.56976744186778292 N cm. Samus tends to bend her knees as she lands, so taking this into consideration, let's say she bends her knees so that she's half her height. 355,726.56976744186778292 N cm. / 50 cm. is 7,114.5313953488373556584 N, and 7,114.5313953488373556584 N / 4.6046511627907032 cm^2 is 15.450749999999982 MPa.

Maybe Samus can withstand more pressure. I can't say for certain, unless there's another area like the one in the image where Samus shows no damage.
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Re: Samus Aran [Discussion]

Postby Mea quidem sententia » Tue Oct 28, 2014 12:17 am

Norfair and air temperature
So, geothermal gradient "is the rate of increasing temperature with respect to increasing depth in the Earth's interior." According to Wikipedia, this means the temperature rises "25°C per km of depth". Samus would need to enter the lithosphere at least, since this is below the crust. This is 100 km. You can see the image below.

Image

Of course, I think the best way to figure this out is by looking at a map of Zebes. Crateria is above Maridia, and Maridia is above Norfair. "Groundwater may be near the Earth's surface or as deep as 30,000 feet, according to the U.S. Geological Survey." Considering Norfair is below Maridia, let's go with 30,000 ft. (9.1463414634146341463 km.) There is a part where Brinstar centers between Maridia and Norfair, so this is an extra layer underneath. Let's go with another kilometer. Then we have to take into consideration the distance the elevator travels from Brinstar to Norfair. Let's say 4 km. This adds up to 15.1463414634146341463 km. This multiplied by 25 gives us 378.6585365853658536575°C.

This becomes a bit complicated, however, because only certain rooms are very hot, whereas others are not. So we cannot say Samus is vulnerable to 378.6585365853658536575°C because if this is the distance she traveled when she first enters Norfair, well, it's not sweltering as it is in other rooms. Some rooms with magma have extreme air temperature, whereas others don't. I haven't even taken the depths of Norfair into consideration. For now, I suppose we can say 379°C won't harm Samus.
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Re: Samus Aran [Discussion]

Postby Beyonder » Tue Oct 28, 2014 6:47 am

So much math.....
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