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Pit (A Kid Icarus respect thread)

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Re: Pit (A Kid Icarus respect thread)

After two years, I finally have resolved Pit's durability in terms of blunt trauma.

In The War’s End: Chapter 25, when Hades destroys the Great Sacred Treasure, Pit falls at least thousands of meters.  Using the kinematic equation for finding distance, Pit drops 2,017.32 m. This is based on the assumption that Pit was experiencing a gravitational acceleration of 9.81 m/s^2, which lasted 20.28 seconds. Then using sqrt(2(9.81 m/s^2 * 2,017.32 m.) to find instantaneous velocity, I ended up with 198.95 m/s. After this, I used the equation for drag force, which is Fd = 1/2 ρ v^2 Cd A.

To clarify, ρ is air density, v^2 is relative velocity, Cd is the drag coefficient, and A is frontal area. I used an air density of 1.225 kg/m^3, the velocity of 198.9468 m/s and squared it, and a drag coefficient of 1.4, since I suspect this is the high-end of a skydiver. The alternative was 1.0, which I presume was for vertical diving. Pit is more or less falling as if his entire body wasn’t streamlined, but horizontal. For frontal area, I used 1.33 m^2, since this is the surface area for children of ages 12 to 13.  I thought it would be reasonable for Pit to be 13, or at least have the appearance. I then punched in the numbers.

Fd = (0.5)(1.225 kg/m^3)(198.95 m/s)^2(1.4)(1.33 m^2)
Fd = 45,140 kg m/s^2

Knowing all that is needed to be known, I went ahead and also calculated for terminal velocity using sqrt(2(mg)/(ρ A Cd)). Here, m is mass, g is gravitational acceleration. The rest is the same. I used a chart for height and weight.  While the site uses 100 lbs., using Hamwi’s method gave me 112 lbs. I’ll use the latter and convert it to kilograms, which is 50.8023 kg. I filled in the equation.

sqrt(2(50.8023 kg. * 9.81 m/s^2)/(1.225 kg/m^3 * 1.33 m^2 * 1.4))
= 20.90418817864566 m/s

In order to find momentum, I need to multiply mass times velocity. Using Pit’s mass and multiplying this by the velocity, I end up with 1,061.980839108010413018 kg m/s. I attempted at dividing this by the time of the impact, but it occurred too quick for me to time it, even with the video slowed down to 25% of its speed. I could assume 1 millisecond, but I doubt that. I think 10 milliseconds would be more reasonable because 100 milliseconds is too slow. If I use 10 milliseconds, then Pit will have experienced 106,198.08 kg m/s^2, or 11.94 tons of force. This is approximately 1.2 times the maximum total thrust generated by ThrustSSC, the first car to break the Mach 1 barrier.

In hac mea interpretatione - How durable is Pit?
Mea quidem sententia 